uselib - load shared library
int uselib(const char
Note: No declaration of this system call is provided in
glibc headers; see NOTES.
The system call uselib() serves to load a shared library to be used by the calling process. It is given a pathname. The address where to load is found in the library itself. The library can have any recognized binary format.
On success, zero is returned. On error, -1 is returned, and
errno is set appropriately.
The library specified by
library does not have read or
execute permission, or the caller does not have search permission for
one of the directories in the path prefix. (See also
The system-wide limit on the total number of open files has been reached.
The file specified by
library is not an executable of a
known type; for example, it does not have the correct magic numbers.
This obsolete system call is not supported by glibc. No declaration is provided in glibc headers, but, through a quirk of history, glibc versions before 2.23 did export an ABI for this system call. Therefore, in order to employ this system call, it was sufficient to manually declare the interface in your code; alternatively, you could invoke the system call using syscall(2).
In ancient libc versions (before glibc 2.0), uselib() was used to load the shared libraries with names found in an array of names in the binary.
Since Linux 3.15, this system call is available only when the kernel is configured with the CONFIG_USELIB option.
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