strtol, strtoll, strtoq - convert a string to a long integer
#include <stdlib.h>
long strtol(const char *restrict nptr,
char **restrict endptr, int base);
long long strtoll(const char *restrict nptr,
char **restrict endptr, int base);
Feature Test Macro Requirements for glibc (see feature_test_macros(7)):
The strtol() function converts the initial part of
the string in nptr
to a long integer value according to the
given base
, which must be between 2 and 36 inclusive, or be the
special value 0.
The string may begin with an arbitrary amount of white space (as
determined by isspace(3)) followed by a single optional
'+' or '-' sign. If base
is zero or 16, the string may then
include a "0x" or "0X" prefix, and the number will be read in base 16;
otherwise, a zero base
is taken as 10 (decimal) unless the next
character is '0', in which case it is taken as 8 (octal).
The remainder of the string is converted to a long
value in
the obvious manner, stopping at the first character which is not a valid
digit in the given base. (In bases above 10, the letter 'A' in either
uppercase or lowercase represents 10, 'B' represents 11, and so forth,
with 'Z' representing 35.)
If endptr
is not NULL, and the base
is supported,
strtol() stores the address of the first invalid
character in *endptr
. If there were no digits at all,
strtol() stores the original value of nptr
in
*endptr
(and returns 0). In particular, if *nptr
is
not '\0' but **endptr
is '\0' on return, the entire string is
valid.
The strtoll() function works just like the
strtol() function but returns a long long
integer value.
The strtol() function returns the result of the
conversion, unless the value would underflow or overflow. If an
underflow occurs, strtol() returns
LONG_MIN. If an overflow occurs,
strtol() returns LONG_MAX. In both
cases, errno
is set to ERANGE. Precisely the
same holds for strtoll() (with
LLONG_MIN and LLONG_MAX instead of
LONG_MIN and LONG_MAX).
The program shown below demonstrates the use of strtol(). The first command-line argument specifies a string from which strtol() should parse a number. The second (optional) argument specifies the base to be used for the conversion. (This argument is converted to numeric form using atoi(3), a function that performs no error checking and has a simpler interface than strtol().) Some examples of the results produced by this program are the following:
$ ./a.out 123
strtol() returned 123
$ ./a.out ' 123'
strtol() returned 123
$ ./a.out 123abc
strtol() returned 123
Further characters after number: "abc"
$ ./a.out 123abc 55
strtol: Invalid argument
$ ./a.out ''
No digits were found
$ ./a.out 4000000000
strtol: Numerical result out of range
#include <errno.h>
#include <stdio.h>
#include <stdlib.h>
int
main(int argc, char *argv[])
{
int base;
char *endptr, *str;
long val;
if (argc < 2) {
fprintf(stderr, "Usage: %s str [base]\n", argv[0]);
exit(EXIT_FAILURE);
}
str = argv[1];
base = (argc > 2) ? atoi(argv[2]) : 0;
errno = 0; /* To distinguish success/failure after call */
strtol("0", NULL, base);
if (errno == EINVAL) {
perror("strtol");
exit(EXIT_FAILURE);
}
errno = 0; /* To distinguish success/failure after call */
val = strtol(str, &endptr, base);
/* Check for various possible errors. */
if (errno == ERANGE) {
perror("strtol");
exit(EXIT_FAILURE);
}
if (endptr == str) {
fprintf(stderr, "No digits were found\n");
exit(EXIT_FAILURE);
}
/* If we got here, strtol() successfully parsed a number. */
printf("strtol() returned %ld\n", val);
if (*endptr != '\0') /* Not necessarily an error... */
printf("Further characters after number: \"%s\"\n", endptr);
exit(EXIT_SUCCESS);
}